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Solve 3x + 10 = 1

The solution of 3x + 10 = 1 is x = -3.

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The lines y = 3x + 10 and y = 1 meet at x = -3-8-6-4-22-20-15-10-55101520x = -3y = 3x + 10y = 1
The lines y = 3x + 10 and y = 1 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+10=13x + 10 = 1
  2. 2

    Subtract 10 from both sides:

    3x+10āˆ’10=1āˆ’10Ā ā‡’Ā 3x=āˆ’93x + 10 - 10 = 1 - 10 \ \Rightarrow\ 3x = -9
  3. 3

    Divide both sides by 3:

    3x3=āˆ’93Ā ā‡’Ā x=āˆ’3\frac{3x}{3} = \frac{-9}{3} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    3ā‹…(āˆ’3)+10=āˆ’9+10=1āœ“3\cdot(-3) + 10 = -9 + 10 = 1 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 10 = 1\ \Rightarrow\ x = -3 \]
\[ 3x + 10 = 1 \]
\[ 3x + 10 - 10 = 1 - 10 \ \Rightarrow\ 3x = -9 \]
\[ \frac{3x}{3} = \frac{-9}{3} \ \Rightarrow\ x = -3 \]
\[ 3\cdot(-3) + 10 = -9 + 10 = 1 \checkmark \]

Trying values of x in 3x + 10 = 1

x3x + 10Equals 1?
-5-5no
-4-2no
-31yes
-24no
-17no

Questions

What is x in 3x + 10 = 1?

The solution of 3x + 10 = 1 is x = -3.

How do you solve 3x + 10 = 1?

Subtract 10 from both sides to get 3x = -9, then divide both sides by 3 to get x = -3.

How do I check the answer?

Replace x by -3: 3(-3) + 10 = 1, which is 1.

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