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Solve 3x āˆ’ 5 = 10

The solution of 3x āˆ’ 5 = 10 is x = 5.

The lines y = 3x āˆ’ 5 and y = 10 meet at x = 5246810-10-551015202530x = 5y = 3x āˆ’ 5y = 10
The lines y = 3x āˆ’ 5 and y = 10 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’5=103x - 5 = 10
  2. 2

    Add 5 to both sides:

    3xāˆ’5+5=10+5 ⇒ 3x=153x - 5 + 5 = 10 + 5 \ \Rightarrow\ 3x = 15
  3. 3

    Divide both sides by 3:

    3x3=153 ⇒ x=5\frac{3x}{3} = \frac{15}{3} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    3ā‹…5āˆ’5=15āˆ’5=10āœ“3\cdot5 - 5 = 15 - 5 = 10 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 5 = 10\ \Rightarrow\ x = 5 \]
\[ 3x - 5 = 10 \]
\[ 3x - 5 + 5 = 10 + 5 \ \Rightarrow\ 3x = 15 \]
\[ \frac{3x}{3} = \frac{15}{3} \ \Rightarrow\ x = 5 \]
\[ 3\cdot5 - 5 = 15 - 5 = 10 \checkmark \]

Trying values of x in 3x āˆ’ 5 = 10

x3x āˆ’ 5Equals 10?
34no
47no
510yes
613no
716no

Questions

What is x in 3x āˆ’ 5 = 10?

The solution of 3x āˆ’ 5 = 10 is x = 5.

How do you solve 3x āˆ’ 5 = 10?

Add 5 to both sides to get 3x = 15, then divide both sides by 3 to get x = 5.

How do I check the answer?

Replace x by 5: 3(5) āˆ’ 5 = 10, which is 10.

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