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Solve 4x āˆ’ 5 = 15

The solution of 4x āˆ’ 5 = 15 is x = 5.

The lines y = 4x āˆ’ 5 and y = 15 meet at x = 5246810-1010203040x = 5y = 4x āˆ’ 5y = 15
The lines y = 4x āˆ’ 5 and y = 15 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    4xāˆ’5=154x - 5 = 15
  2. 2

    Add 5 to both sides:

    4xāˆ’5+5=15+5 ⇒ 4x=204x - 5 + 5 = 15 + 5 \ \Rightarrow\ 4x = 20
  3. 3

    Divide both sides by 4:

    4x4=204 ⇒ x=5\frac{4x}{4} = \frac{20}{4} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    4ā‹…5āˆ’5=20āˆ’5=15āœ“4\cdot5 - 5 = 20 - 5 = 15 \checkmark
LaTeX source of the formulas on this page
\[ 4x - 5 = 15\ \Rightarrow\ x = 5 \]
\[ 4x - 5 = 15 \]
\[ 4x - 5 + 5 = 15 + 5 \ \Rightarrow\ 4x = 20 \]
\[ \frac{4x}{4} = \frac{20}{4} \ \Rightarrow\ x = 5 \]
\[ 4\cdot5 - 5 = 20 - 5 = 15 \checkmark \]

Trying values of x in 4x āˆ’ 5 = 15

x4x āˆ’ 5Equals 15?
37no
411no
515yes
619no
723no

Questions

What is x in 4x āˆ’ 5 = 15?

The solution of 4x āˆ’ 5 = 15 is x = 5.

How do you solve 4x āˆ’ 5 = 15?

Add 5 to both sides to get 4x = 20, then divide both sides by 4 to get x = 5.

How do I check the answer?

Replace x by 5: 4(5) āˆ’ 5 = 15, which is 15.

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