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Solve 3x āˆ’ 2 = 43

The solution of 3x āˆ’ 2 = 43 is x = 15.

The lines y = 3x āˆ’ 2 and y = 43 meet at x = 151012141618202530354045505560x = 15y = 3x āˆ’ 2y = 43
The lines y = 3x āˆ’ 2 and y = 43 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’2=433x - 2 = 43
  2. 2

    Add 2 to both sides:

    3xāˆ’2+2=43+2 ⇒ 3x=453x - 2 + 2 = 43 + 2 \ \Rightarrow\ 3x = 45
  3. 3

    Divide both sides by 3:

    3x3=453 ⇒ x=15\frac{3x}{3} = \frac{45}{3} \ \Rightarrow\ x = 15
  4. 4

    Check: put x = 15 back into the equation.

    3ā‹…15āˆ’2=45āˆ’2=43āœ“3\cdot15 - 2 = 45 - 2 = 43 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 2 = 43\ \Rightarrow\ x = 15 \]
\[ 3x - 2 = 43 \]
\[ 3x - 2 + 2 = 43 + 2 \ \Rightarrow\ 3x = 45 \]
\[ \frac{3x}{3} = \frac{45}{3} \ \Rightarrow\ x = 15 \]
\[ 3\cdot15 - 2 = 45 - 2 = 43 \checkmark \]

Trying values of x in 3x āˆ’ 2 = 43

x3x āˆ’ 2Equals 43?
1337no
1440no
1543yes
1646no
1749no

Questions

What is x in 3x āˆ’ 2 = 43?

The solution of 3x āˆ’ 2 = 43 is x = 15.

How do you solve 3x āˆ’ 2 = 43?

Add 2 to both sides to get 3x = 45, then divide both sides by 3 to get x = 15.

How do I check the answer?

Replace x by 15: 3(15) āˆ’ 2 = 43, which is 43.

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    Solve 3x āˆ’ 2 = 43: x = 15 (steps and check) | WordGPT