Solve 4x ā 2 = 58
The solution of 4x ā 2 = 58 is x = 15.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 2 to both sides:
- 3
Divide both sides by 4:
- 4
Check: put x = 15 back into the equation.
LaTeX source of the formulas on this page
\[ 4x - 2 = 58\ \Rightarrow\ x = 15 \]
\[ 4x - 2 = 58 \]
\[ 4x - 2 + 2 = 58 + 2 \ \Rightarrow\ 4x = 60 \]
\[ \frac{4x}{4} = \frac{60}{4} \ \Rightarrow\ x = 15 \]
\[ 4\cdot15 - 2 = 60 - 2 = 58 \checkmark \]Trying values of x in 4x ā 2 = 58
| x | 4x ā 2 | Equals 58? |
|---|---|---|
| 13 | 50 | no |
| 14 | 54 | no |
| 15 | 58 | yes |
| 16 | 62 | no |
| 17 | 66 | no |
Questions
What is x in 4x ā 2 = 58?
The solution of 4x ā 2 = 58 is x = 15.
How do you solve 4x ā 2 = 58?
Add 2 to both sides to get 4x = 60, then divide both sides by 4 to get x = 15.
How do I check the answer?
Replace x by 15: 4(15) ā 2 = 58, which is 58.