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Solve 3x āˆ’ 15 = āˆ’45

The solution of 3x āˆ’ 15 = āˆ’45 is x = -10.

The lines y = 3x āˆ’ 15 and y = -45 meet at x = -10-16-14-12-10-8-6-4-65-60-55-50-45-40-35-30-25x = -10y = 3x āˆ’ 15y = -45
The lines y = 3x āˆ’ 15 and y = -45 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’15=āˆ’453x - 15 = -45
  2. 2

    Add 15 to both sides:

    3xāˆ’15+15=āˆ’45+15 ⇒ 3x=āˆ’303x - 15 + 15 = -45 + 15 \ \Rightarrow\ 3x = -30
  3. 3

    Divide both sides by 3:

    3x3=āˆ’303 ⇒ x=āˆ’10\frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    3ā‹…(āˆ’10)āˆ’15=āˆ’30āˆ’15=āˆ’45āœ“3\cdot(-10) - 15 = -30 - 15 = -45 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 15 = -45\ \Rightarrow\ x = -10 \]
\[ 3x - 15 = -45 \]
\[ 3x - 15 + 15 = -45 + 15 \ \Rightarrow\ 3x = -30 \]
\[ \frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10 \]
\[ 3\cdot(-10) - 15 = -30 - 15 = -45 \checkmark \]

Trying values of x in 3x āˆ’ 15 = āˆ’45

x3x āˆ’ 15Equals -45?
-12-51no
-11-48no
-10-45yes
-9-42no
-8-39no

Questions

What is x in 3x āˆ’ 15 = āˆ’45?

The solution of 3x āˆ’ 15 = āˆ’45 is x = -10.

How do you solve 3x āˆ’ 15 = āˆ’45?

Add 15 to both sides to get 3x = -30, then divide both sides by 3 to get x = -10.

How do I check the answer?

Replace x by -10: 3(-10) āˆ’ 15 = -45, which is -45.

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    Solve 3x āˆ’ 15 = āˆ’45: x = -10 (steps and check) | WordGPT