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Solve 3x āˆ’ 15 = āˆ’42

The solution of 3x āˆ’ 15 = āˆ’42 is x = -9.

The lines y = 3x āˆ’ 15 and y = -42 meet at x = -9-14-12-10-8-6-4-60-55-50-45-40-35-30-25x = -9y = 3x āˆ’ 15y = -42
The lines y = 3x āˆ’ 15 and y = -42 meet at x = -9. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’15=āˆ’423x - 15 = -42
  2. 2

    Add 15 to both sides:

    3xāˆ’15+15=āˆ’42+15 ⇒ 3x=āˆ’273x - 15 + 15 = -42 + 15 \ \Rightarrow\ 3x = -27
  3. 3

    Divide both sides by 3:

    3x3=āˆ’273 ⇒ x=āˆ’9\frac{3x}{3} = \frac{-27}{3} \ \Rightarrow\ x = -9
  4. 4

    Check: put x = -9 back into the equation.

    3ā‹…(āˆ’9)āˆ’15=āˆ’27āˆ’15=āˆ’42āœ“3\cdot(-9) - 15 = -27 - 15 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 15 = -42\ \Rightarrow\ x = -9 \]
\[ 3x - 15 = -42 \]
\[ 3x - 15 + 15 = -42 + 15 \ \Rightarrow\ 3x = -27 \]
\[ \frac{3x}{3} = \frac{-27}{3} \ \Rightarrow\ x = -9 \]
\[ 3\cdot(-9) - 15 = -27 - 15 = -42 \checkmark \]

Trying values of x in 3x āˆ’ 15 = āˆ’42

x3x āˆ’ 15Equals -42?
-11-48no
-10-45no
-9-42yes
-8-39no
-7-36no

Questions

What is x in 3x āˆ’ 15 = āˆ’42?

The solution of 3x āˆ’ 15 = āˆ’42 is x = -9.

How do you solve 3x āˆ’ 15 = āˆ’42?

Add 15 to both sides to get 3x = -27, then divide both sides by 3 to get x = -9.

How do I check the answer?

Replace x by -9: 3(-9) āˆ’ 15 = -42, which is -42.

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    Solve 3x āˆ’ 15 = āˆ’42: x = -9 (steps and check) | WordGPT