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Solve 3x āˆ’ 12 = āˆ’42

The solution of 3x āˆ’ 12 = āˆ’42 is x = -10.

The lines y = 3x āˆ’ 12 and y = -42 meet at x = -10-16-14-12-10-8-6-4-60-55-50-45-40-35-30-25x = -10y = 3x āˆ’ 12y = -42
The lines y = 3x āˆ’ 12 and y = -42 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    3xāˆ’12=āˆ’423x - 12 = -42
  2. 2

    Add 12 to both sides:

    3xāˆ’12+12=āˆ’42+12 ⇒ 3x=āˆ’303x - 12 + 12 = -42 + 12 \ \Rightarrow\ 3x = -30
  3. 3

    Divide both sides by 3:

    3x3=āˆ’303 ⇒ x=āˆ’10\frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    3ā‹…(āˆ’10)āˆ’12=āˆ’30āˆ’12=āˆ’42āœ“3\cdot(-10) - 12 = -30 - 12 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 3x - 12 = -42\ \Rightarrow\ x = -10 \]
\[ 3x - 12 = -42 \]
\[ 3x - 12 + 12 = -42 + 12 \ \Rightarrow\ 3x = -30 \]
\[ \frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10 \]
\[ 3\cdot(-10) - 12 = -30 - 12 = -42 \checkmark \]

Trying values of x in 3x āˆ’ 12 = āˆ’42

x3x āˆ’ 12Equals -42?
-12-48no
-11-45no
-10-42yes
-9-39no
-8-36no

Questions

What is x in 3x āˆ’ 12 = āˆ’42?

The solution of 3x āˆ’ 12 = āˆ’42 is x = -10.

How do you solve 3x āˆ’ 12 = āˆ’42?

Add 12 to both sides to get 3x = -30, then divide both sides by 3 to get x = -10.

How do I check the answer?

Replace x by -10: 3(-10) āˆ’ 12 = -42, which is -42.

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    Solve 3x āˆ’ 12 = āˆ’42: x = -10 (steps and check) | WordGPT