Solve 2x + 5 = 39
The solution of 2x + 5 = 39 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 5 = 39\ \Rightarrow\ x = 17 \]
\[ 2x + 5 = 39 \]
\[ 2x + 5 - 5 = 39 - 5 \ \Rightarrow\ 2x = 34 \]
\[ \frac{2x}{2} = \frac{34}{2} \ \Rightarrow\ x = 17 \]
\[ 2\cdot17 + 5 = 34 + 5 = 39 \checkmark \]Trying values of x in 2x + 5 = 39
| x | 2x + 5 | Equals 39? |
|---|---|---|
| 15 | 35 | no |
| 16 | 37 | no |
| 17 | 39 | yes |
| 18 | 41 | no |
| 19 | 43 | no |
Questions
What is x in 2x + 5 = 39?
The solution of 2x + 5 = 39 is x = 17.
How do you solve 2x + 5 = 39?
Subtract 5 from both sides to get 2x = 34, then divide both sides by 2 to get x = 17.
How do I check the answer?
Replace x by 17: 2(17) + 5 = 39, which is 39.