Solve 2x + 5 = 37
The solution of 2x + 5 = 37 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 5 = 37\ \Rightarrow\ x = 16 \]
\[ 2x + 5 = 37 \]
\[ 2x + 5 - 5 = 37 - 5 \ \Rightarrow\ 2x = 32 \]
\[ \frac{2x}{2} = \frac{32}{2} \ \Rightarrow\ x = 16 \]
\[ 2\cdot16 + 5 = 32 + 5 = 37 \checkmark \]Trying values of x in 2x + 5 = 37
| x | 2x + 5 | Equals 37? |
|---|---|---|
| 14 | 33 | no |
| 15 | 35 | no |
| 16 | 37 | yes |
| 17 | 39 | no |
| 18 | 41 | no |
Questions
What is x in 2x + 5 = 37?
The solution of 2x + 5 = 37 is x = 16.
How do you solve 2x + 5 = 37?
Subtract 5 from both sides to get 2x = 32, then divide both sides by 2 to get x = 16.
How do I check the answer?
Replace x by 16: 2(16) + 5 = 37, which is 37.