Solve 2x + 10 = 32
The solution of 2x + 10 = 32 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 10 = 32\ \Rightarrow\ x = 11 \]
\[ 2x + 10 = 32 \]
\[ 2x + 10 - 10 = 32 - 10 \ \Rightarrow\ 2x = 22 \]
\[ \frac{2x}{2} = \frac{22}{2} \ \Rightarrow\ x = 11 \]
\[ 2\cdot11 + 10 = 22 + 10 = 32 \checkmark \]Trying values of x in 2x + 10 = 32
| x | 2x + 10 | Equals 32? |
|---|---|---|
| 9 | 28 | no |
| 10 | 30 | no |
| 11 | 32 | yes |
| 12 | 34 | no |
| 13 | 36 | no |
Questions
What is x in 2x + 10 = 32?
The solution of 2x + 10 = 32 is x = 11.
How do you solve 2x + 10 = 32?
Subtract 10 from both sides to get 2x = 22, then divide both sides by 2 to get x = 11.
How do I check the answer?
Replace x by 11: 2(11) + 10 = 32, which is 32.