Solve 3x + 10 = 43
The solution of 3x + 10 = 43 is x = 11.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 10 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 11 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 10 = 43\ \Rightarrow\ x = 11 \]
\[ 3x + 10 = 43 \]
\[ 3x + 10 - 10 = 43 - 10 \ \Rightarrow\ 3x = 33 \]
\[ \frac{3x}{3} = \frac{33}{3} \ \Rightarrow\ x = 11 \]
\[ 3\cdot11 + 10 = 33 + 10 = 43 \checkmark \]Trying values of x in 3x + 10 = 43
| x | 3x + 10 | Equals 43? |
|---|---|---|
| 9 | 37 | no |
| 10 | 40 | no |
| 11 | 43 | yes |
| 12 | 46 | no |
| 13 | 49 | no |
Questions
What is x in 3x + 10 = 43?
The solution of 3x + 10 = 43 is x = 11.
How do you solve 3x + 10 = 43?
Subtract 10 from both sides to get 3x = 33, then divide both sides by 3 to get x = 11.
How do I check the answer?
Replace x by 11: 3(11) + 10 = 43, which is 43.