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Solve 2x + 1 = āˆ’19

The solution of 2x + 1 = āˆ’19 is x = -10.

The lines y = 2x + 1 and y = -19 meet at x = -10-16-14-12-10-8-6-4-30-25-20-15-10-5x = -10y = 2x + 1y = -19
The lines y = 2x + 1 and y = -19 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    2x+1=āˆ’192x + 1 = -19
  2. 2

    Subtract 1 from both sides:

    2x+1āˆ’1=āˆ’19āˆ’1 ⇒ 2x=āˆ’202x + 1 - 1 = -19 - 1 \ \Rightarrow\ 2x = -20
  3. 3

    Divide both sides by 2:

    2x2=āˆ’202 ⇒ x=āˆ’10\frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    2ā‹…(āˆ’10)+1=āˆ’20+1=āˆ’19āœ“2\cdot(-10) + 1 = -20 + 1 = -19 \checkmark
LaTeX source of the formulas on this page
\[ 2x + 1 = -19\ \Rightarrow\ x = -10 \]
\[ 2x + 1 = -19 \]
\[ 2x + 1 - 1 = -19 - 1 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) + 1 = -20 + 1 = -19 \checkmark \]

Trying values of x in 2x + 1 = āˆ’19

x2x + 1Equals -19?
-12-23no
-11-21no
-10-19yes
-9-17no
-8-15no

Questions

What is x in 2x + 1 = āˆ’19?

The solution of 2x + 1 = āˆ’19 is x = -10.

How do you solve 2x + 1 = āˆ’19?

Subtract 1 from both sides to get 2x = -20, then divide both sides by 2 to get x = -10.

How do I check the answer?

Replace x by -10: 2(-10) + 1 = -19, which is -19.

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    Solve 2x + 1 = āˆ’19: x = -10 (steps and check) | WordGPT