Solve 3x + 1 = ā29
The solution of 3x + 1 = ā29 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 1 = -29\ \Rightarrow\ x = -10 \]
\[ 3x + 1 = -29 \]
\[ 3x + 1 - 1 = -29 - 1 \ \Rightarrow\ 3x = -30 \]
\[ \frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10 \]
\[ 3\cdot(-10) + 1 = -30 + 1 = -29 \checkmark \]Trying values of x in 3x + 1 = ā29
| x | 3x + 1 | Equals -29? |
|---|---|---|
| -12 | -35 | no |
| -11 | -32 | no |
| -10 | -29 | yes |
| -9 | -26 | no |
| -8 | -23 | no |
Questions
What is x in 3x + 1 = ā29?
The solution of 3x + 1 = ā29 is x = -10.
How do you solve 3x + 1 = ā29?
Subtract 1 from both sides to get 3x = -30, then divide both sides by 3 to get x = -10.
How do I check the answer?
Replace x by -10: 3(-10) + 1 = -29, which is -29.