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Solve 3x + 1 = āˆ’29

The solution of 3x + 1 = āˆ’29 is x = -10.

The lines y = 3x + 1 and y = -29 meet at x = -10-16-14-12-10-8-6-4-50-45-40-35-30-25-20-15-10x = -10y = 3x + 1y = -29
The lines y = 3x + 1 and y = -29 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    3x+1=āˆ’293x + 1 = -29
  2. 2

    Subtract 1 from both sides:

    3x+1āˆ’1=āˆ’29āˆ’1 ⇒ 3x=āˆ’303x + 1 - 1 = -29 - 1 \ \Rightarrow\ 3x = -30
  3. 3

    Divide both sides by 3:

    3x3=āˆ’303 ⇒ x=āˆ’10\frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    3ā‹…(āˆ’10)+1=āˆ’30+1=āˆ’29āœ“3\cdot(-10) + 1 = -30 + 1 = -29 \checkmark
LaTeX source of the formulas on this page
\[ 3x + 1 = -29\ \Rightarrow\ x = -10 \]
\[ 3x + 1 = -29 \]
\[ 3x + 1 - 1 = -29 - 1 \ \Rightarrow\ 3x = -30 \]
\[ \frac{3x}{3} = \frac{-30}{3} \ \Rightarrow\ x = -10 \]
\[ 3\cdot(-10) + 1 = -30 + 1 = -29 \checkmark \]

Trying values of x in 3x + 1 = āˆ’29

x3x + 1Equals -29?
-12-35no
-11-32no
-10-29yes
-9-26no
-8-23no

Questions

What is x in 3x + 1 = āˆ’29?

The solution of 3x + 1 = āˆ’29 is x = -10.

How do you solve 3x + 1 = āˆ’29?

Subtract 1 from both sides to get 3x = -30, then divide both sides by 3 to get x = -10.

How do I check the answer?

Replace x by -10: 3(-10) + 1 = -29, which is -29.

Similar equations

    Solve 3x + 1 = āˆ’29: x = -10 (steps and check) | WordGPT