Solve 2x + 1 = 41
The solution of 2x + 1 = 41 is x = 20.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 20 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 1 = 41\ \Rightarrow\ x = 20 \]
\[ 2x + 1 = 41 \]
\[ 2x + 1 - 1 = 41 - 1 \ \Rightarrow\ 2x = 40 \]
\[ \frac{2x}{2} = \frac{40}{2} \ \Rightarrow\ x = 20 \]
\[ 2\cdot20 + 1 = 40 + 1 = 41 \checkmark \]Trying values of x in 2x + 1 = 41
| x | 2x + 1 | Equals 41? |
|---|---|---|
| 18 | 37 | no |
| 19 | 39 | no |
| 20 | 41 | yes |
| 21 | 43 | no |
| 22 | 45 | no |
Questions
What is x in 2x + 1 = 41?
The solution of 2x + 1 = 41 is x = 20.
How do you solve 2x + 1 = 41?
Subtract 1 from both sides to get 2x = 40, then divide both sides by 2 to get x = 20.
How do I check the answer?
Replace x by 20: 2(20) + 1 = 41, which is 41.