Solve 2x + 1 = 39

The solution of 2x + 1 = 39 is x = 19.

2x + 1 = 39\ \Rightarrow\ x = 19

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The lines y = 2x + 1 and y = 39 meet at x = 19. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
$2x + 1 = 39$
2
Subtract 1 from both sides:
$2x + 1 - 1 = 39 - 1 \ \Rightarrow\ 2x = 38$
3
Divide both sides by 2:
$\frac{2x}{2} = \frac{38}{2} \ \Rightarrow\ x = 19$
4
Check: put x = 19 back into the equation.
$2\cdot19 + 1 = 38 + 1 = 39 \checkmark$

LaTeX source of the formulas on this page

\[ 2x + 1 = 39\ \Rightarrow\ x = 19 \]
\[ 2x + 1 = 39 \]
\[ 2x + 1 - 1 = 39 - 1 \ \Rightarrow\ 2x = 38 \]
\[ \frac{2x}{2} = \frac{38}{2} \ \Rightarrow\ x = 19 \]
\[ 2\cdot19 + 1 = 38 + 1 = 39 \checkmark \]

Trying values of x in 2x + 1 = 39

x	2x + 1	Equals 39?
17	35	no
18	37	no
19	39	yes
20	41	no
21	43	no

Questions

What is x in 2x + 1 = 39?

The solution of 2x + 1 = 39 is x = 19.

How do you solve 2x + 1 = 39?

Subtract 1 from both sides to get 2x = 38, then divide both sides by 2 to get x = 19.

How do I check the answer?

Replace x by 19: 2(19) + 1 = 39, which is 39.

Solve 2x + 1 = 39

How to work it out

Trying values of x in 2x + 1 = 39

Questions

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