Solve 2x + 1 = 35
The solution of 2x + 1 = 35 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 2:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 2x + 1 = 35\ \Rightarrow\ x = 17 \]
\[ 2x + 1 = 35 \]
\[ 2x + 1 - 1 = 35 - 1 \ \Rightarrow\ 2x = 34 \]
\[ \frac{2x}{2} = \frac{34}{2} \ \Rightarrow\ x = 17 \]
\[ 2\cdot17 + 1 = 34 + 1 = 35 \checkmark \]Trying values of x in 2x + 1 = 35
| x | 2x + 1 | Equals 35? |
|---|---|---|
| 15 | 31 | no |
| 16 | 33 | no |
| 17 | 35 | yes |
| 18 | 37 | no |
| 19 | 39 | no |
Questions
What is x in 2x + 1 = 35?
The solution of 2x + 1 = 35 is x = 17.
How do you solve 2x + 1 = 35?
Subtract 1 from both sides to get 2x = 34, then divide both sides by 2 to get x = 17.
How do I check the answer?
Replace x by 17: 2(17) + 1 = 35, which is 35.