Solve 3x + 1 = 52
The solution of 3x + 1 = 52 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 3:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 3x + 1 = 52\ \Rightarrow\ x = 17 \]
\[ 3x + 1 = 52 \]
\[ 3x + 1 - 1 = 52 - 1 \ \Rightarrow\ 3x = 51 \]
\[ \frac{3x}{3} = \frac{51}{3} \ \Rightarrow\ x = 17 \]
\[ 3\cdot17 + 1 = 51 + 1 = 52 \checkmark \]Trying values of x in 3x + 1 = 52
| x | 3x + 1 | Equals 52? |
|---|---|---|
| 15 | 46 | no |
| 16 | 49 | no |
| 17 | 52 | yes |
| 18 | 55 | no |
| 19 | 58 | no |
Questions
What is x in 3x + 1 = 52?
The solution of 3x + 1 = 52 is x = 17.
How do you solve 3x + 1 = 52?
Subtract 1 from both sides to get 3x = 51, then divide both sides by 3 to get x = 17.
How do I check the answer?
Replace x by 17: 3(17) + 1 = 52, which is 52.