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Solve 2x āˆ’ 12 = āˆ’32

The solution of 2x āˆ’ 12 = āˆ’32 is x = -10.

The lines y = 2x āˆ’ 12 and y = -32 meet at x = -10-16-14-12-10-8-6-4-45-40-35-30-25-20x = -10y = 2x āˆ’ 12y = -32
The lines y = 2x āˆ’ 12 and y = -32 meet at x = -10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    2xāˆ’12=āˆ’322x - 12 = -32
  2. 2

    Add 12 to both sides:

    2xāˆ’12+12=āˆ’32+12 ⇒ 2x=āˆ’202x - 12 + 12 = -32 + 12 \ \Rightarrow\ 2x = -20
  3. 3

    Divide both sides by 2:

    2x2=āˆ’202 ⇒ x=āˆ’10\frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10
  4. 4

    Check: put x = -10 back into the equation.

    2ā‹…(āˆ’10)āˆ’12=āˆ’20āˆ’12=āˆ’32āœ“2\cdot(-10) - 12 = -20 - 12 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 2x - 12 = -32\ \Rightarrow\ x = -10 \]
\[ 2x - 12 = -32 \]
\[ 2x - 12 + 12 = -32 + 12 \ \Rightarrow\ 2x = -20 \]
\[ \frac{2x}{2} = \frac{-20}{2} \ \Rightarrow\ x = -10 \]
\[ 2\cdot(-10) - 12 = -20 - 12 = -32 \checkmark \]

Trying values of x in 2x āˆ’ 12 = āˆ’32

x2x āˆ’ 12Equals -32?
-12-36no
-11-34no
-10-32yes
-9-30no
-8-28no

Questions

What is x in 2x āˆ’ 12 = āˆ’32?

The solution of 2x āˆ’ 12 = āˆ’32 is x = -10.

How do you solve 2x āˆ’ 12 = āˆ’32?

Add 12 to both sides to get 2x = -20, then divide both sides by 2 to get x = -10.

How do I check the answer?

Replace x by -10: 2(-10) āˆ’ 12 = -32, which is -32.

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    Solve 2x āˆ’ 12 = āˆ’32: x = -10 (steps and check) | WordGPT