Solve 12x + 4 = 208
The solution of 12x + 4 = 208 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 4 = 208\ \Rightarrow\ x = 17 \]
\[ 12x + 4 = 208 \]
\[ 12x + 4 - 4 = 208 - 4 \ \Rightarrow\ 12x = 204 \]
\[ \frac{12x}{12} = \frac{204}{12} \ \Rightarrow\ x = 17 \]
\[ 12\cdot17 + 4 = 204 + 4 = 208 \checkmark \]Trying values of x in 12x + 4 = 208
| x | 12x + 4 | Equals 208? |
|---|---|---|
| 15 | 184 | no |
| 16 | 196 | no |
| 17 | 208 | yes |
| 18 | 220 | no |
| 19 | 232 | no |
Questions
What is x in 12x + 4 = 208?
The solution of 12x + 4 = 208 is x = 17.
How do you solve 12x + 4 = 208?
Subtract 4 from both sides to get 12x = 204, then divide both sides by 12 to get x = 17.
How do I check the answer?
Replace x by 17: 12(17) + 4 = 208, which is 208.