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Solve 12x āˆ’ 4 = 200

The solution of 12x āˆ’ 4 = 200 is x = 17.

The lines y = 12x āˆ’ 4 and y = 200 meet at x = 17121416182022120140160180200220240260280x = 17y = 12x āˆ’ 4y = 200
The lines y = 12x āˆ’ 4 and y = 200 meet at x = 17. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’4=20012x - 4 = 200
  2. 2

    Add 4 to both sides:

    12xāˆ’4+4=200+4 ⇒ 12x=20412x - 4 + 4 = 200 + 4 \ \Rightarrow\ 12x = 204
  3. 3

    Divide both sides by 12:

    12x12=20412 ⇒ x=17\frac{12x}{12} = \frac{204}{12} \ \Rightarrow\ x = 17
  4. 4

    Check: put x = 17 back into the equation.

    12ā‹…17āˆ’4=204āˆ’4=200āœ“12\cdot17 - 4 = 204 - 4 = 200 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 4 = 200\ \Rightarrow\ x = 17 \]
\[ 12x - 4 = 200 \]
\[ 12x - 4 + 4 = 200 + 4 \ \Rightarrow\ 12x = 204 \]
\[ \frac{12x}{12} = \frac{204}{12} \ \Rightarrow\ x = 17 \]
\[ 12\cdot17 - 4 = 204 - 4 = 200 \checkmark \]

Trying values of x in 12x āˆ’ 4 = 200

x12x āˆ’ 4Equals 200?
15176no
16188no
17200yes
18212no
19224no

Questions

What is x in 12x āˆ’ 4 = 200?

The solution of 12x āˆ’ 4 = 200 is x = 17.

How do you solve 12x āˆ’ 4 = 200?

Add 4 to both sides to get 12x = 204, then divide both sides by 12 to get x = 17.

How do I check the answer?

Replace x by 17: 12(17) āˆ’ 4 = 200, which is 200.

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