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Solve 12x + 2 = āˆ’58

The solution of 12x + 2 = āˆ’58 is x = -5.

The lines y = 12x + 2 and y = -58 meet at x = -5-10-8-6-4-2-140-120-100-80-60-40-2020x = -5y = 12x + 2y = -58
The lines y = 12x + 2 and y = -58 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+2=āˆ’5812x + 2 = -58
  2. 2

    Subtract 2 from both sides:

    12x+2āˆ’2=āˆ’58āˆ’2 ⇒ 12x=āˆ’6012x + 2 - 2 = -58 - 2 \ \Rightarrow\ 12x = -60
  3. 3

    Divide both sides by 12:

    12x12=āˆ’6012 ⇒ x=āˆ’5\frac{12x}{12} = \frac{-60}{12} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    12ā‹…(āˆ’5)+2=āˆ’60+2=āˆ’58āœ“12\cdot(-5) + 2 = -60 + 2 = -58 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 2 = -58\ \Rightarrow\ x = -5 \]
\[ 12x + 2 = -58 \]
\[ 12x + 2 - 2 = -58 - 2 \ \Rightarrow\ 12x = -60 \]
\[ \frac{12x}{12} = \frac{-60}{12} \ \Rightarrow\ x = -5 \]
\[ 12\cdot(-5) + 2 = -60 + 2 = -58 \checkmark \]

Trying values of x in 12x + 2 = āˆ’58

x12x + 2Equals -58?
-7-82no
-6-70no
-5-58yes
-4-46no
-3-34no

Questions

What is x in 12x + 2 = āˆ’58?

The solution of 12x + 2 = āˆ’58 is x = -5.

How do you solve 12x + 2 = āˆ’58?

Subtract 2 from both sides to get 12x = -60, then divide both sides by 12 to get x = -5.

How do I check the answer?

Replace x by -5: 12(-5) + 2 = -58, which is -58.

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    Solve 12x + 2 = āˆ’58: x = -5 (steps and check) | WordGPT