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Solve 12x āˆ’ 2 = āˆ’62

The solution of 12x āˆ’ 2 = āˆ’62 is x = -5.

The lines y = 12x āˆ’ 2 and y = -62 meet at x = -5-10-8-6-4-2-140-120-100-80-60-40-2020x = -5y = 12x āˆ’ 2y = -62
The lines y = 12x āˆ’ 2 and y = -62 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’2=āˆ’6212x - 2 = -62
  2. 2

    Add 2 to both sides:

    12xāˆ’2+2=āˆ’62+2 ⇒ 12x=āˆ’6012x - 2 + 2 = -62 + 2 \ \Rightarrow\ 12x = -60
  3. 3

    Divide both sides by 12:

    12x12=āˆ’6012 ⇒ x=āˆ’5\frac{12x}{12} = \frac{-60}{12} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    12ā‹…(āˆ’5)āˆ’2=āˆ’60āˆ’2=āˆ’62āœ“12\cdot(-5) - 2 = -60 - 2 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 2 = -62\ \Rightarrow\ x = -5 \]
\[ 12x - 2 = -62 \]
\[ 12x - 2 + 2 = -62 + 2 \ \Rightarrow\ 12x = -60 \]
\[ \frac{12x}{12} = \frac{-60}{12} \ \Rightarrow\ x = -5 \]
\[ 12\cdot(-5) - 2 = -60 - 2 = -62 \checkmark \]

Trying values of x in 12x āˆ’ 2 = āˆ’62

x12x āˆ’ 2Equals -62?
-7-86no
-6-74no
-5-62yes
-4-50no
-3-38no

Questions

What is x in 12x āˆ’ 2 = āˆ’62?

The solution of 12x āˆ’ 2 = āˆ’62 is x = -5.

How do you solve 12x āˆ’ 2 = āˆ’62?

Add 2 to both sides to get 12x = -60, then divide both sides by 12 to get x = -5.

How do I check the answer?

Replace x by -5: 12(-5) āˆ’ 2 = -62, which is -62.

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    Solve 12x āˆ’ 2 = āˆ’62: x = -5 (steps and check) | WordGPT