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Solve 12x + 10 = āˆ’2

The solution of 12x + 10 = āˆ’2 is x = -1.

The lines y = 12x + 10 and y = -2 meet at x = -1-6-4-224-80-60-40-2020406080x = -1y = 12x + 10y = -2
The lines y = 12x + 10 and y = -2 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+10=āˆ’212x + 10 = -2
  2. 2

    Subtract 10 from both sides:

    12x+10āˆ’10=āˆ’2āˆ’10 ⇒ 12x=āˆ’1212x + 10 - 10 = -2 - 10 \ \Rightarrow\ 12x = -12
  3. 3

    Divide both sides by 12:

    12x12=āˆ’1212 ⇒ x=āˆ’1\frac{12x}{12} = \frac{-12}{12} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    12ā‹…(āˆ’1)+10=āˆ’12+10=āˆ’2āœ“12\cdot(-1) + 10 = -12 + 10 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 10 = -2\ \Rightarrow\ x = -1 \]
\[ 12x + 10 = -2 \]
\[ 12x + 10 - 10 = -2 - 10 \ \Rightarrow\ 12x = -12 \]
\[ \frac{12x}{12} = \frac{-12}{12} \ \Rightarrow\ x = -1 \]
\[ 12\cdot(-1) + 10 = -12 + 10 = -2 \checkmark \]

Trying values of x in 12x + 10 = āˆ’2

x12x + 10Equals -2?
-3-26no
-2-14no
-1-2yes
010no
122no

Questions

What is x in 12x + 10 = āˆ’2?

The solution of 12x + 10 = āˆ’2 is x = -1.

How do you solve 12x + 10 = āˆ’2?

Subtract 10 from both sides to get 12x = -12, then divide both sides by 12 to get x = -1.

How do I check the answer?

Replace x by -1: 12(-1) + 10 = -2, which is -2.

Similar equations

    Solve 12x + 10 = āˆ’2: x = -1 (steps and check) | WordGPT