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Solve 12x āˆ’ 10 = āˆ’22

The solution of 12x āˆ’ 10 = āˆ’22 is x = -1.

The lines y = 12x āˆ’ 10 and y = -22 meet at x = -1-6-4-224-100-80-60-40-20204060x = -1y = 12x āˆ’ 10y = -22
The lines y = 12x āˆ’ 10 and y = -22 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’10=āˆ’2212x - 10 = -22
  2. 2

    Add 10 to both sides:

    12xāˆ’10+10=āˆ’22+10 ⇒ 12x=āˆ’1212x - 10 + 10 = -22 + 10 \ \Rightarrow\ 12x = -12
  3. 3

    Divide both sides by 12:

    12x12=āˆ’1212 ⇒ x=āˆ’1\frac{12x}{12} = \frac{-12}{12} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    12ā‹…(āˆ’1)āˆ’10=āˆ’12āˆ’10=āˆ’22āœ“12\cdot(-1) - 10 = -12 - 10 = -22 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 10 = -22\ \Rightarrow\ x = -1 \]
\[ 12x - 10 = -22 \]
\[ 12x - 10 + 10 = -22 + 10 \ \Rightarrow\ 12x = -12 \]
\[ \frac{12x}{12} = \frac{-12}{12} \ \Rightarrow\ x = -1 \]
\[ 12\cdot(-1) - 10 = -12 - 10 = -22 \checkmark \]

Trying values of x in 12x āˆ’ 10 = āˆ’22

x12x āˆ’ 10Equals -22?
-3-46no
-2-34no
-1-22yes
0-10no
12no

Questions

What is x in 12x āˆ’ 10 = āˆ’22?

The solution of 12x āˆ’ 10 = āˆ’22 is x = -1.

How do you solve 12x āˆ’ 10 = āˆ’22?

Add 10 to both sides to get 12x = -12, then divide both sides by 12 to get x = -1.

How do I check the answer?

Replace x by -1: 12(-1) āˆ’ 10 = -22, which is -22.

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    Solve 12x āˆ’ 10 = āˆ’22: x = -1 (steps and check) | WordGPT