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Solve 12x āˆ’ 3 = 237

The solution of 12x āˆ’ 3 = 237 is x = 20.

The lines y = 12x āˆ’ 3 and y = 237 meet at x = 2014161820222426160180200220240260280300320x = 20y = 12x āˆ’ 3y = 237
The lines y = 12x āˆ’ 3 and y = 237 meet at x = 20. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’3=23712x - 3 = 237
  2. 2

    Add 3 to both sides:

    12xāˆ’3+3=237+3 ⇒ 12x=24012x - 3 + 3 = 237 + 3 \ \Rightarrow\ 12x = 240
  3. 3

    Divide both sides by 12:

    12x12=24012 ⇒ x=20\frac{12x}{12} = \frac{240}{12} \ \Rightarrow\ x = 20
  4. 4

    Check: put x = 20 back into the equation.

    12ā‹…20āˆ’3=240āˆ’3=237āœ“12\cdot20 - 3 = 240 - 3 = 237 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 3 = 237\ \Rightarrow\ x = 20 \]
\[ 12x - 3 = 237 \]
\[ 12x - 3 + 3 = 237 + 3 \ \Rightarrow\ 12x = 240 \]
\[ \frac{12x}{12} = \frac{240}{12} \ \Rightarrow\ x = 20 \]
\[ 12\cdot20 - 3 = 240 - 3 = 237 \checkmark \]

Trying values of x in 12x āˆ’ 3 = 237

x12x āˆ’ 3Equals 237?
18213no
19225no
20237yes
21249no
22261no

Questions

What is x in 12x āˆ’ 3 = 237?

The solution of 12x āˆ’ 3 = 237 is x = 20.

How do you solve 12x āˆ’ 3 = 237?

Add 3 to both sides to get 12x = 240, then divide both sides by 12 to get x = 20.

How do I check the answer?

Replace x by 20: 12(20) āˆ’ 3 = 237, which is 237.

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