Solve 11x + 9 = ā2
The solution of 11x + 9 = ā2 is x = -1.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 9 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -1 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 9 = -2\ \Rightarrow\ x = -1 \]
\[ 11x + 9 = -2 \]
\[ 11x + 9 - 9 = -2 - 9 \ \Rightarrow\ 11x = -11 \]
\[ \frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1 \]
\[ 11\cdot(-1) + 9 = -11 + 9 = -2 \checkmark \]Trying values of x in 11x + 9 = ā2
| x | 11x + 9 | Equals -2? |
|---|---|---|
| -3 | -24 | no |
| -2 | -13 | no |
| -1 | -2 | yes |
| 0 | 9 | no |
| 1 | 20 | no |
Questions
What is x in 11x + 9 = ā2?
The solution of 11x + 9 = ā2 is x = -1.
How do you solve 11x + 9 = ā2?
Subtract 9 from both sides to get 11x = -11, then divide both sides by 11 to get x = -1.
How do I check the answer?
Replace x by -1: 11(-1) + 9 = -2, which is -2.