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Solve 11x āˆ’ 9 = āˆ’20

The solution of 11x āˆ’ 9 = āˆ’20 is x = -1.

The lines y = 11x āˆ’ 9 and y = -20 meet at x = -1-6-4-224-80-60-40-202040x = -1y = 11x āˆ’ 9y = -20
The lines y = 11x āˆ’ 9 and y = -20 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’9=āˆ’2011x - 9 = -20
  2. 2

    Add 9 to both sides:

    11xāˆ’9+9=āˆ’20+9 ⇒ 11x=āˆ’1111x - 9 + 9 = -20 + 9 \ \Rightarrow\ 11x = -11
  3. 3

    Divide both sides by 11:

    11x11=āˆ’1111 ⇒ x=āˆ’1\frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    11ā‹…(āˆ’1)āˆ’9=āˆ’11āˆ’9=āˆ’20āœ“11\cdot(-1) - 9 = -11 - 9 = -20 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 9 = -20\ \Rightarrow\ x = -1 \]
\[ 11x - 9 = -20 \]
\[ 11x - 9 + 9 = -20 + 9 \ \Rightarrow\ 11x = -11 \]
\[ \frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1 \]
\[ 11\cdot(-1) - 9 = -11 - 9 = -20 \checkmark \]

Trying values of x in 11x āˆ’ 9 = āˆ’20

x11x āˆ’ 9Equals -20?
-3-42no
-2-31no
-1-20yes
0-9no
12no

Questions

What is x in 11x āˆ’ 9 = āˆ’20?

The solution of 11x āˆ’ 9 = āˆ’20 is x = -1.

How do you solve 11x āˆ’ 9 = āˆ’20?

Add 9 to both sides to get 11x = -11, then divide both sides by 11 to get x = -1.

How do I check the answer?

Replace x by -1: 11(-1) āˆ’ 9 = -20, which is -20.

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    Solve 11x āˆ’ 9 = āˆ’20: x = -1 (steps and check) | WordGPT