Solve 11x + 6 = ā71
The solution of 11x + 6 = ā71 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 6 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 6 = -71\ \Rightarrow\ x = -7 \]
\[ 11x + 6 = -71 \]
\[ 11x + 6 - 6 = -71 - 6 \ \Rightarrow\ 11x = -77 \]
\[ \frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7 \]
\[ 11\cdot(-7) + 6 = -77 + 6 = -71 \checkmark \]Trying values of x in 11x + 6 = ā71
| x | 11x + 6 | Equals -71? |
|---|---|---|
| -9 | -93 | no |
| -8 | -82 | no |
| -7 | -71 | yes |
| -6 | -60 | no |
| -5 | -49 | no |
Questions
What is x in 11x + 6 = ā71?
The solution of 11x + 6 = ā71 is x = -7.
How do you solve 11x + 6 = ā71?
Subtract 6 from both sides to get 11x = -77, then divide both sides by 11 to get x = -7.
How do I check the answer?
Replace x by -7: 11(-7) + 6 = -71, which is -71.