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Solve 11x āˆ’ 6 = āˆ’83

The solution of 11x āˆ’ 6 = āˆ’83 is x = -7.

The lines y = 11x āˆ’ 6 and y = -83 meet at x = -7-12-10-8-6-4-2-160-140-120-100-80-60-40-20x = -7y = 11x āˆ’ 6y = -83
The lines y = 11x āˆ’ 6 and y = -83 meet at x = -7. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’6=āˆ’8311x - 6 = -83
  2. 2

    Add 6 to both sides:

    11xāˆ’6+6=āˆ’83+6 ⇒ 11x=āˆ’7711x - 6 + 6 = -83 + 6 \ \Rightarrow\ 11x = -77
  3. 3

    Divide both sides by 11:

    11x11=āˆ’7711 ⇒ x=āˆ’7\frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7
  4. 4

    Check: put x = -7 back into the equation.

    11ā‹…(āˆ’7)āˆ’6=āˆ’77āˆ’6=āˆ’83āœ“11\cdot(-7) - 6 = -77 - 6 = -83 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 6 = -83\ \Rightarrow\ x = -7 \]
\[ 11x - 6 = -83 \]
\[ 11x - 6 + 6 = -83 + 6 \ \Rightarrow\ 11x = -77 \]
\[ \frac{11x}{11} = \frac{-77}{11} \ \Rightarrow\ x = -7 \]
\[ 11\cdot(-7) - 6 = -77 - 6 = -83 \checkmark \]

Trying values of x in 11x āˆ’ 6 = āˆ’83

x11x āˆ’ 6Equals -83?
-9-105no
-8-94no
-7-83yes
-6-72no
-5-61no

Questions

What is x in 11x āˆ’ 6 = āˆ’83?

The solution of 11x āˆ’ 6 = āˆ’83 is x = -7.

How do you solve 11x āˆ’ 6 = āˆ’83?

Add 6 to both sides to get 11x = -77, then divide both sides by 11 to get x = -7.

How do I check the answer?

Replace x by -7: 11(-7) āˆ’ 6 = -83, which is -83.

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    Solve 11x āˆ’ 6 = āˆ’83: x = -7 (steps and check) | WordGPT