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Solve 11x + 4 = āˆ’62

The solution of 11x + 4 = āˆ’62 is x = -6.

The lines y = 11x + 4 and y = -62 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 11x + 4y = -62
The lines y = 11x + 4 and y = -62 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+4=āˆ’6211x + 4 = -62
  2. 2

    Subtract 4 from both sides:

    11x+4āˆ’4=āˆ’62āˆ’4 ⇒ 11x=āˆ’6611x + 4 - 4 = -62 - 4 \ \Rightarrow\ 11x = -66
  3. 3

    Divide both sides by 11:

    11x11=āˆ’6611 ⇒ x=āˆ’6\frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    11ā‹…(āˆ’6)+4=āˆ’66+4=āˆ’62āœ“11\cdot(-6) + 4 = -66 + 4 = -62 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 4 = -62\ \Rightarrow\ x = -6 \]
\[ 11x + 4 = -62 \]
\[ 11x + 4 - 4 = -62 - 4 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) + 4 = -66 + 4 = -62 \checkmark \]

Trying values of x in 11x + 4 = āˆ’62

x11x + 4Equals -62?
-8-84no
-7-73no
-6-62yes
-5-51no
-4-40no

Questions

What is x in 11x + 4 = āˆ’62?

The solution of 11x + 4 = āˆ’62 is x = -6.

How do you solve 11x + 4 = āˆ’62?

Subtract 4 from both sides to get 11x = -66, then divide both sides by 11 to get x = -6.

How do I check the answer?

Replace x by -6: 11(-6) + 4 = -62, which is -62.

Similar equations

    Solve 11x + 4 = āˆ’62: x = -6 (steps and check) | WordGPT