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Solve 12x + 4 = āˆ’68

The solution of 12x + 4 = āˆ’68 is x = -6.

The lines y = 12x + 4 and y = -68 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 12x + 4y = -68
The lines y = 12x + 4 and y = -68 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    12x+4=āˆ’6812x + 4 = -68
  2. 2

    Subtract 4 from both sides:

    12x+4āˆ’4=āˆ’68āˆ’4 ⇒ 12x=āˆ’7212x + 4 - 4 = -68 - 4 \ \Rightarrow\ 12x = -72
  3. 3

    Divide both sides by 12:

    12x12=āˆ’7212 ⇒ x=āˆ’6\frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    12ā‹…(āˆ’6)+4=āˆ’72+4=āˆ’68āœ“12\cdot(-6) + 4 = -72 + 4 = -68 \checkmark
LaTeX source of the formulas on this page
\[ 12x + 4 = -68\ \Rightarrow\ x = -6 \]
\[ 12x + 4 = -68 \]
\[ 12x + 4 - 4 = -68 - 4 \ \Rightarrow\ 12x = -72 \]
\[ \frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6 \]
\[ 12\cdot(-6) + 4 = -72 + 4 = -68 \checkmark \]

Trying values of x in 12x + 4 = āˆ’68

x12x + 4Equals -68?
-8-92no
-7-80no
-6-68yes
-5-56no
-4-44no

Questions

What is x in 12x + 4 = āˆ’68?

The solution of 12x + 4 = āˆ’68 is x = -6.

How do you solve 12x + 4 = āˆ’68?

Subtract 4 from both sides to get 12x = -72, then divide both sides by 12 to get x = -6.

How do I check the answer?

Replace x by -6: 12(-6) + 4 = -68, which is -68.

Similar equations

    Solve 12x + 4 = āˆ’68: x = -6 (steps and check) | WordGPT