Solve 12x + 4 = ā68
The solution of 12x + 4 = ā68 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 4 = -68\ \Rightarrow\ x = -6 \]
\[ 12x + 4 = -68 \]
\[ 12x + 4 - 4 = -68 - 4 \ \Rightarrow\ 12x = -72 \]
\[ \frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6 \]
\[ 12\cdot(-6) + 4 = -72 + 4 = -68 \checkmark \]Trying values of x in 12x + 4 = ā68
| x | 12x + 4 | Equals -68? |
|---|---|---|
| -8 | -92 | no |
| -7 | -80 | no |
| -6 | -68 | yes |
| -5 | -56 | no |
| -4 | -44 | no |
Questions
What is x in 12x + 4 = ā68?
The solution of 12x + 4 = ā68 is x = -6.
How do you solve 12x + 4 = ā68?
Subtract 4 from both sides to get 12x = -72, then divide both sides by 12 to get x = -6.
How do I check the answer?
Replace x by -6: 12(-6) + 4 = -68, which is -68.