Solve 11x + 3 = ā41
The solution of 11x + 3 = ā41 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 3 = -41\ \Rightarrow\ x = -4 \]
\[ 11x + 3 = -41 \]
\[ 11x + 3 - 3 = -41 - 3 \ \Rightarrow\ 11x = -44 \]
\[ \frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4 \]
\[ 11\cdot(-4) + 3 = -44 + 3 = -41 \checkmark \]Trying values of x in 11x + 3 = ā41
| x | 11x + 3 | Equals -41? |
|---|---|---|
| -6 | -63 | no |
| -5 | -52 | no |
| -4 | -41 | yes |
| -3 | -30 | no |
| -2 | -19 | no |
Questions
What is x in 11x + 3 = ā41?
The solution of 11x + 3 = ā41 is x = -4.
How do you solve 11x + 3 = ā41?
Subtract 3 from both sides to get 11x = -44, then divide both sides by 11 to get x = -4.
How do I check the answer?
Replace x by -4: 11(-4) + 3 = -41, which is -41.