Solve 12x + 3 = ā45
The solution of 12x + 3 = ā45 is x = -4.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = -4 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 3 = -45\ \Rightarrow\ x = -4 \]
\[ 12x + 3 = -45 \]
\[ 12x + 3 - 3 = -45 - 3 \ \Rightarrow\ 12x = -48 \]
\[ \frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4 \]
\[ 12\cdot(-4) + 3 = -48 + 3 = -45 \checkmark \]Trying values of x in 12x + 3 = ā45
| x | 12x + 3 | Equals -45? |
|---|---|---|
| -6 | -69 | no |
| -5 | -57 | no |
| -4 | -45 | yes |
| -3 | -33 | no |
| -2 | -21 | no |
Questions
What is x in 12x + 3 = ā45?
The solution of 12x + 3 = ā45 is x = -4.
How do you solve 12x + 3 = ā45?
Subtract 3 from both sides to get 12x = -48, then divide both sides by 12 to get x = -4.
How do I check the answer?
Replace x by -4: 12(-4) + 3 = -45, which is -45.