Solve 11x + 1 = ā65
The solution of 11x + 1 = ā65 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 1 = -65\ \Rightarrow\ x = -6 \]
\[ 11x + 1 = -65 \]
\[ 11x + 1 - 1 = -65 - 1 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) + 1 = -66 + 1 = -65 \checkmark \]Trying values of x in 11x + 1 = ā65
| x | 11x + 1 | Equals -65? |
|---|---|---|
| -8 | -87 | no |
| -7 | -76 | no |
| -6 | -65 | yes |
| -5 | -54 | no |
| -4 | -43 | no |
Questions
What is x in 11x + 1 = ā65?
The solution of 11x + 1 = ā65 is x = -6.
How do you solve 11x + 1 = ā65?
Subtract 1 from both sides to get 11x = -66, then divide both sides by 11 to get x = -6.
How do I check the answer?
Replace x by -6: 11(-6) + 1 = -65, which is -65.