Solve 11x ā 1 = ā67
The solution of 11x ā 1 = ā67 is x = -6.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
- 2
Add 1 to both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -6 back into the equation.
LaTeX source of the formulas on this page
\[ 11x - 1 = -67\ \Rightarrow\ x = -6 \]
\[ 11x - 1 = -67 \]
\[ 11x - 1 + 1 = -67 + 1 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) - 1 = -66 - 1 = -67 \checkmark \]Trying values of x in 11x ā 1 = ā67
| x | 11x ā 1 | Equals -67? |
|---|---|---|
| -8 | -89 | no |
| -7 | -78 | no |
| -6 | -67 | yes |
| -5 | -56 | no |
| -4 | -45 | no |
Questions
What is x in 11x ā 1 = ā67?
The solution of 11x ā 1 = ā67 is x = -6.
How do you solve 11x ā 1 = ā67?
Add 1 to both sides to get 11x = -66, then divide both sides by 11 to get x = -6.
How do I check the answer?
Replace x by -6: 11(-6) ā 1 = -67, which is -67.