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Solve 11x āˆ’ 12 = 120

The solution of 11x āˆ’ 12 = 120 is x = 12.

The lines y = 11x āˆ’ 12 and y = 120 meet at x = 126810121416186080100120140160180x = 12y = 11x āˆ’ 12y = 120
The lines y = 11x āˆ’ 12 and y = 120 meet at x = 12. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’12=12011x - 12 = 120
  2. 2

    Add 12 to both sides:

    11xāˆ’12+12=120+12 ⇒ 11x=13211x - 12 + 12 = 120 + 12 \ \Rightarrow\ 11x = 132
  3. 3

    Divide both sides by 11:

    11x11=13211 ⇒ x=12\frac{11x}{11} = \frac{132}{11} \ \Rightarrow\ x = 12
  4. 4

    Check: put x = 12 back into the equation.

    11ā‹…12āˆ’12=132āˆ’12=120āœ“11\cdot12 - 12 = 132 - 12 = 120 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 12 = 120\ \Rightarrow\ x = 12 \]
\[ 11x - 12 = 120 \]
\[ 11x - 12 + 12 = 120 + 12 \ \Rightarrow\ 11x = 132 \]
\[ \frac{11x}{11} = \frac{132}{11} \ \Rightarrow\ x = 12 \]
\[ 11\cdot12 - 12 = 132 - 12 = 120 \checkmark \]

Trying values of x in 11x āˆ’ 12 = 120

x11x āˆ’ 12Equals 120?
1098no
11109no
12120yes
13131no
14142no

Questions

What is x in 11x āˆ’ 12 = 120?

The solution of 11x āˆ’ 12 = 120 is x = 12.

How do you solve 11x āˆ’ 12 = 120?

Add 12 to both sides to get 11x = 132, then divide both sides by 11 to get x = 12.

How do I check the answer?

Replace x by 12: 11(12) āˆ’ 12 = 120, which is 120.

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