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Solve 11x āˆ’ 12 = 109

The solution of 11x āˆ’ 12 = 109 is x = 11.

The lines y = 11x āˆ’ 12 and y = 109 meet at x = 116810121416406080100120140160180x = 11y = 11x āˆ’ 12y = 109
The lines y = 11x āˆ’ 12 and y = 109 meet at x = 11. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’12=10911x - 12 = 109
  2. 2

    Add 12 to both sides:

    11xāˆ’12+12=109+12 ⇒ 11x=12111x - 12 + 12 = 109 + 12 \ \Rightarrow\ 11x = 121
  3. 3

    Divide both sides by 11:

    11x11=12111 ⇒ x=11\frac{11x}{11} = \frac{121}{11} \ \Rightarrow\ x = 11
  4. 4

    Check: put x = 11 back into the equation.

    11ā‹…11āˆ’12=121āˆ’12=109āœ“11\cdot11 - 12 = 121 - 12 = 109 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 12 = 109\ \Rightarrow\ x = 11 \]
\[ 11x - 12 = 109 \]
\[ 11x - 12 + 12 = 109 + 12 \ \Rightarrow\ 11x = 121 \]
\[ \frac{11x}{11} = \frac{121}{11} \ \Rightarrow\ x = 11 \]
\[ 11\cdot11 - 12 = 121 - 12 = 109 \checkmark \]

Trying values of x in 11x āˆ’ 12 = 109

x11x āˆ’ 12Equals 109?
987no
1098no
11109yes
12120no
13131no

Questions

What is x in 11x āˆ’ 12 = 109?

The solution of 11x āˆ’ 12 = 109 is x = 11.

How do you solve 11x āˆ’ 12 = 109?

Add 12 to both sides to get 11x = 121, then divide both sides by 11 to get x = 11.

How do I check the answer?

Replace x by 11: 11(11) āˆ’ 12 = 109, which is 109.

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