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Solve 10x āˆ’ 12 = āˆ’42

The solution of 10x āˆ’ 12 = āˆ’42 is x = -3.

The lines y = 10x āˆ’ 12 and y = -42 meet at x = -3-8-6-4-22-100-80-60-40-2020x = -3y = 10x āˆ’ 12y = -42
The lines y = 10x āˆ’ 12 and y = -42 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=āˆ’4210x - 12 = -42
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=āˆ’42+12 ⇒ 10x=āˆ’3010x - 12 + 12 = -42 + 12 \ \Rightarrow\ 10x = -30
  3. 3

    Divide both sides by 10:

    10x10=āˆ’3010 ⇒ x=āˆ’3\frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    10ā‹…(āˆ’3)āˆ’12=āˆ’30āˆ’12=āˆ’42āœ“10\cdot(-3) - 12 = -30 - 12 = -42 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = -42\ \Rightarrow\ x = -3 \]
\[ 10x - 12 = -42 \]
\[ 10x - 12 + 12 = -42 + 12 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) - 12 = -30 - 12 = -42 \checkmark \]

Trying values of x in 10x āˆ’ 12 = āˆ’42

x10x āˆ’ 12Equals -42?
-5-62no
-4-52no
-3-42yes
-2-32no
-1-22no

Questions

What is x in 10x āˆ’ 12 = āˆ’42?

The solution of 10x āˆ’ 12 = āˆ’42 is x = -3.

How do you solve 10x āˆ’ 12 = āˆ’42?

Add 12 to both sides to get 10x = -30, then divide both sides by 10 to get x = -3.

How do I check the answer?

Replace x by -3: 10(-3) āˆ’ 12 = -42, which is -42.

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    Solve 10x āˆ’ 12 = āˆ’42: x = -3 (steps and check) | WordGPT