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Solve 10x āˆ’ 12 = āˆ’32

The solution of 10x āˆ’ 12 = āˆ’32 is x = -2.

The lines y = 10x āˆ’ 12 and y = -32 meet at x = -2-8-6-4-224-100-80-60-40-202040x = -2y = 10x āˆ’ 12y = -32
The lines y = 10x āˆ’ 12 and y = -32 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    10xāˆ’12=āˆ’3210x - 12 = -32
  2. 2

    Add 12 to both sides:

    10xāˆ’12+12=āˆ’32+12 ⇒ 10x=āˆ’2010x - 12 + 12 = -32 + 12 \ \Rightarrow\ 10x = -20
  3. 3

    Divide both sides by 10:

    10x10=āˆ’2010 ⇒ x=āˆ’2\frac{10x}{10} = \frac{-20}{10} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    10ā‹…(āˆ’2)āˆ’12=āˆ’20āˆ’12=āˆ’32āœ“10\cdot(-2) - 12 = -20 - 12 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 10x - 12 = -32\ \Rightarrow\ x = -2 \]
\[ 10x - 12 = -32 \]
\[ 10x - 12 + 12 = -32 + 12 \ \Rightarrow\ 10x = -20 \]
\[ \frac{10x}{10} = \frac{-20}{10} \ \Rightarrow\ x = -2 \]
\[ 10\cdot(-2) - 12 = -20 - 12 = -32 \checkmark \]

Trying values of x in 10x āˆ’ 12 = āˆ’32

x10x āˆ’ 12Equals -32?
-4-52no
-3-42no
-2-32yes
-1-22no
0-12no

Questions

What is x in 10x āˆ’ 12 = āˆ’32?

The solution of 10x āˆ’ 12 = āˆ’32 is x = -2.

How do you solve 10x āˆ’ 12 = āˆ’32?

Add 12 to both sides to get 10x = -20, then divide both sides by 10 to get x = -2.

How do I check the answer?

Replace x by -2: 10(-2) āˆ’ 12 = -32, which is -32.

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    Solve 10x āˆ’ 12 = āˆ’32: x = -2 (steps and check) | WordGPT