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Limit of x2βˆ’1xβˆ’1\frac{x^{2} - 1}{x - 1} as xβ†’1x \to 1

The limit of x2βˆ’1xβˆ’1\frac{x^{2} - 1}{x - 1} as xβ†’1x \to 1 is 22.

Graph of (x^2 - 1) / (x - 1) near x = 1-0.50.511.522.50.511.522.533.5limit = 2f(x)
Graph of (x^2 - 1) / (x - 1) near x = 1. The open circle marks the point x = 1, where the function may be undefined; the curve still heads to 2.

How to work it out

  1. 1

    We want what (x2x^{2} - 1) / (x - 1) approaches as x β†’ 1.

    lim⁑xβ†’1x2βˆ’1xβˆ’1\lim_{x \to 1} \frac{x^{2} - 1}{x - 1}
  2. 2

    Direct substitution gives an indeterminate form: 0/0. It does not tell us the limit.

  3. 3

    L'HΓ΄pital's rule: when the form is 0/0, the limit equals the limit of the ratio of the derivatives.

    lim⁑x2βˆ’1xβˆ’1=lim⁑2x1\lim \frac{x^{2} - 1}{x - 1} = \lim \frac{2 x}{1}
  4. 4

    Now substitute x = 1: the denominator is not 0 any more.

    21=2\frac{2}{1} = 2
  5. 5

    Method: this is the derivative of x2x^{2} at 1, namely 2.

  6. 6

    Result:

    lim⁑xβ†’1x2βˆ’1xβˆ’1=2\lim_{x \to 1} \frac{x^{2} - 1}{x - 1} = 2
LaTeX source of the formulas on this page
\[ \lim_{x \to 1} \frac{x^{2} - 1}{x - 1} = 2 \]
\[ \lim_{x \to 1} \frac{x^{2} - 1}{x - 1} \]
\[ \lim \frac{x^{2} - 1}{x - 1} = \lim \frac{2 x}{1} \]
\[ \frac{2}{1} = 2 \]

Values of (x2x^{2} - 1) / (x - 1) as x β†’ 1 (computed)

xf(x)Distance from the limit
1.12.10000001.00e-1
0.91.90000001.00e-1
1.012.01000001.00e-2
0.991.99000001.00e-2
1.0012.00100001.00e-3
0.9991.99900001.00e-3
1.00012.00010001.00e-4
0.99991.99990001.00e-4
1.000012.00001001.00e-5
0.999991.99999001.00e-5

Questions

What is the limit of (x2x^{2} - 1) / (x - 1) as x approaches 1?

The limit of x2βˆ’1xβˆ’1\frac{x^{2} - 1}{x - 1} as xβ†’1x \to 1 is 22.

Which form is it?

0/0.

More well-known limits

    Limit of (x^2 - 1) / (x - 1) as x β†’ 1: 2 | WordGPT