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Limit of 1−cos⁡(x)x2\frac{1 - \cos\left(x\right)}{x^{2}} as x→0x \to 0

The limit of 1−cos⁡(x)x2\frac{1 - \cos\left(x\right)}{x^{2}} as x→0x \to 0 is 12\frac12.

Graph of (1 - cos(x)) / x^2 near x = 0-1.5-1-0.50.511.50.420.440.460.480.5limit = 1/2f(x)
Graph of (1 - cos(x)) / x^2 near x = 0. The open circle marks the point x = 0, where the function may be undefined; the curve still heads to 1/2.

How to work it out

  1. 1

    We want what (1 - cos(x)) / x2x^{2} approaches as x → 0.

    lim⁡x→01−cos⁡(x)x2\lim_{x \to 0} \frac{1 - \cos\left(x\right)}{x^{2}}
  2. 2

    Direct substitution gives an indeterminate form: 0/0. It does not tell us the limit.

  3. 3

    L'Hôpital's rule: when the form is 0/0, the limit equals the limit of the ratio of the derivatives.

    lim⁡1−cos⁡(x)x2=lim⁡sin⁡(x)2x\lim \frac{1 - \cos\left(x\right)}{x^{2}} = \lim \frac{\sin\left(x\right)}{2 x}
  4. 4

    Still 0/0 (both vanish again), so apply it once more.

    lim⁡sin⁡(x)2x=lim⁡cos⁡(x)2\lim \frac{\sin\left(x\right)}{2 x} = \lim \frac{\cos\left(x\right)}{2}
  5. 5

    Now substitute x = 0: the denominator is not 0 any more.

    12=0.5\frac{1}{2} = 0.5
  6. 6

    Method: multiply by 1 + cos x, or use the series cos x = 1 − x²/2 + ….

  7. 7

    Result:

    lim⁡x→01−cos⁡(x)x2=12\lim_{x \to 0} \frac{1 - \cos\left(x\right)}{x^{2}} = \frac12
LaTeX source of the formulas on this page
\[ \lim_{x \to 0} \frac{1 - \cos\left(x\right)}{x^{2}} = \frac12 \]
\[ \lim_{x \to 0} \frac{1 - \cos\left(x\right)}{x^{2}} \]
\[ \lim \frac{1 - \cos\left(x\right)}{x^{2}} = \lim \frac{\sin\left(x\right)}{2 x} \]
\[ \lim \frac{\sin\left(x\right)}{2 x} = \lim \frac{\cos\left(x\right)}{2} \]
\[ \frac{1}{2} = 0.5 \]

Values of (1 - cos(x)) / x2x^{2} as x → 0 (computed)

xf(x)Distance from the limit
0.10.499583474.17e-4
-0.10.499583474.17e-4
0.010.499995834.17e-6
-0.010.499995834.17e-6
0.0010.499999964.17e-8
-0.0010.499999964.17e-8
0.00010.500000003.04e-9
-0.00010.500000003.04e-9
0.000010.500000044.14e-8
-0.000010.500000044.14e-8

Questions

What is the limit of (1 - cos(x)) / x2x^{2} as x approaches 0?

The limit of 1−cos⁡(x)x2\frac{1 - \cos\left(x\right)}{x^{2}} as x→0x \to 0 is 12\frac12.

Which form is it?

0/0.

More well-known limits

    Limit of (1 - cos(x)) / x^2 as x → 0: 1/2 | WordGPT