WordGPT

Limit of tan⁡(x)−sin⁡(x)x3\frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} as x→0x \to 0

The limit of tan⁡(x)−sin⁡(x)x3\frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} as x→0x \to 0 is 12\frac12.

Graph of (tan(x) - sin(x)) / x^3 near x = 0-1.5-1-0.50.511.50.511.522.5limit = 1/2f(x)
Graph of (tan(x) - sin(x)) / x^3 near x = 0. The open circle marks the point x = 0, where the function may be undefined; the curve still heads to 1/2.

How to work it out

  1. 1

    We want what (tan(x) - sin(x)) / x3x^{3} approaches as x → 0.

    lim⁡x→0tan⁡(x)−sin⁡(x)x3\lim_{x \to 0} \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}}
  2. 2

    Direct substitution gives an indeterminate form: 0/0. It does not tell us the limit.

  3. 3

    L'Hôpital's rule: when the form is 0/0, the limit equals the limit of the ratio of the derivatives.

    lim⁡tan⁡(x)−sin⁡(x)x3=lim⁡1cos⁡(x)2−cos⁡(x)3x2\lim \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} = \lim \frac{\frac{1}{\cos\left(x\right)^{2}} - \cos\left(x\right)}{3 x^{2}}
  4. 4

    Still 0/0 (both vanish again), so apply it once more.

    lim⁡1cos⁡(x)2−cos⁡(x)3x2=lim⁡−(2cos⁡(x)−sin⁡(x))(cos⁡(x)2)2−−sin⁡(x)6x\lim \frac{\frac{1}{\cos\left(x\right)^{2}} - \cos\left(x\right)}{3 x^{2}} = \lim \frac{\frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}} - -\sin\left(x\right)}{6 x}
  5. 5

    Still 0/0 (both vanish again), so apply it once more.

    lim⁡−(2cos⁡(x)−sin⁡(x))(cos⁡(x)2)2−−sin⁡(x)6x=lim⁡−((2−sin⁡(x)−sin⁡(x)+2cos⁡(x)−cos⁡(x))(cos⁡(x)2)2)−−(2cos⁡(x)−sin⁡(x)2cos⁡(x)22cos⁡(x)−sin⁡(x))((cos⁡(x)2)2)2−−cos⁡(x)6\lim \frac{\frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}} - -\sin\left(x\right)}{6 x} = \lim \frac{\frac{-\left(\left(2 -\sin\left(x\right) -\sin\left(x\right) + 2 \cos\left(x\right) -\cos\left(x\right)\right) \left(\cos\left(x\right)^{2}\right)^{2}\right) - -\left(2 \cos\left(x\right) -\sin\left(x\right) 2 \cos\left(x\right)^{2} 2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\left(\cos\left(x\right)^{2}\right)^{2}\right)^{2}} - -\cos\left(x\right)}{6}
  6. 6

    Now substitute x = 0: the denominator is not 0 any more.

    36=0.5\frac{3}{6} = 0.5
  7. 7

    Method: series: tan x − sin x = x³/2 + ….

  8. 8

    Result:

    lim⁡x→0tan⁡(x)−sin⁡(x)x3=12\lim_{x \to 0} \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} = \frac12
LaTeX source of the formulas on this page
\[ \lim_{x \to 0} \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} = \frac12 \]
\[ \lim_{x \to 0} \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} \]
\[ \lim \frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} = \lim \frac{\frac{1}{\cos\left(x\right)^{2}} - \cos\left(x\right)}{3 x^{2}} \]
\[ \lim \frac{\frac{1}{\cos\left(x\right)^{2}} - \cos\left(x\right)}{3 x^{2}} = \lim \frac{\frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}} - -\sin\left(x\right)}{6 x} \]
\[ \lim \frac{\frac{-\left(2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\cos\left(x\right)^{2}\right)^{2}} - -\sin\left(x\right)}{6 x} = \lim \frac{\frac{-\left(\left(2 -\sin\left(x\right) -\sin\left(x\right) + 2 \cos\left(x\right) -\cos\left(x\right)\right) \left(\cos\left(x\right)^{2}\right)^{2}\right) - -\left(2 \cos\left(x\right) -\sin\left(x\right) 2 \cos\left(x\right)^{2} 2 \cos\left(x\right) -\sin\left(x\right)\right)}{\left(\left(\cos\left(x\right)^{2}\right)^{2}\right)^{2}} - -\cos\left(x\right)}{6} \]
\[ \frac{3}{6} = 0.5 \]

Values of (tan(x) - sin(x)) / x3x^{3} as x → 0 (computed)

xf(x)Distance from the limit
0.10.501255441.26e-3
-0.10.501255441.26e-3
0.010.500012501.25e-5
-0.010.500012501.25e-5
0.0010.500000131.25e-7
-0.0010.500000131.25e-7
0.00010.500000002.00e-9
-0.00010.500000002.00e-9
0.000010.500000161.61e-7
-0.000010.500000161.61e-7

Questions

What is the limit of (tan(x) - sin(x)) / x3x^{3} as x approaches 0?

The limit of tan⁡(x)−sin⁡(x)x3\frac{\tan\left(x\right) - \sin\left(x\right)}{x^{3}} as x→0x \to 0 is 12\frac12.

Which form is it?

0/0.

More well-known limits

    Limit of (tan(x) - sin(x)) / x^3 as x → 0: 1/2 | WordGPT