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Limit of x2+xβˆ’x\sqrt{x^{2} + x} - x as xβ†’βˆžx \to \infty

The limit of x2+xβˆ’x\sqrt{x^{2} + x} - x as xβ†’βˆžx \to \infty is 12\frac12.

Graph of sqrt(x^2 + x) - x near x = ∞5101520253035400.440.450.460.470.480.490.5limit = 1/2f(x)
Graph of sqrt(x^2 + x) - x near x = ∞. The curve levels off at 1/2 as x grows.

How to work it out

  1. 1

    We want what sqrt(x2x^{2} + x) - x approaches as x β†’ ∞.

    lim⁑xβ†’βˆžx2+xβˆ’x\lim_{x \to \infty} \sqrt{x^{2} + x} - x
  2. 2

    Direct substitution gives an indeterminate form: βˆžβˆ’βˆž. It does not tell us the limit.

  3. 3

    Method: multiply and divide by √(xΒ²+x) + x, giving x / (√(xΒ²+x) + x) β†’ 1/2.

  4. 4

    Result:

    lim⁑xβ†’βˆžx2+xβˆ’x=12\lim_{x \to \infty} \sqrt{x^{2} + x} - x = \frac12
LaTeX source of the formulas on this page
\[ \lim_{x \to \infty} \sqrt{x^{2} + x} - x = \frac12 \]
\[ \lim_{x \to \infty} \sqrt{x^{2} + x} - x \]

Values of sqrt(x2x^{2} + x) - x as x β†’ ∞ (computed)

xf(x)Distance from the limit
100.488088481.19e-2
1000.498756211.24e-3
10000.499875061.25e-4
100000.499987501.25e-5
1000000.499998751.25e-6
10000000.499999871.25e-7

Questions

What is the limit of sqrt(x2x^{2} + x) - x as x approaches ∞?

The limit of x2+xβˆ’x\sqrt{x^{2} + x} - x as xβ†’βˆžx \to \infty is 12\frac12.

Which form is it?

βˆžβˆ’βˆž.

More well-known limits

    Limit of sqrt(x^2 + x) - x as x β†’ ∞: 1/2 | WordGPT