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Limit of sin⁑(x)βˆ’xx3\frac{\sin\left(x\right) - x}{x^{3}} as xβ†’0x \to 0

The limit of sin⁑(x)βˆ’xx3\frac{\sin\left(x\right) - x}{x^{3}} as xβ†’0x \to 0 is βˆ’16-\frac16.

Graph of (sin(x) - x) / x^3 near x = 0-1.5-1-0.50.511.5-0.165-0.16-0.155-0.15limit = βˆ’1/6f(x)
Graph of (sin(x) - x) / x^3 near x = 0. The open circle marks the point x = 0, where the function may be undefined; the curve still heads to βˆ’1/6.

How to work it out

  1. 1

    We want what (sin(x) - x) / x3x^{3} approaches as x β†’ 0.

    lim⁑xβ†’0sin⁑(x)βˆ’xx3\lim_{x \to 0} \frac{\sin\left(x\right) - x}{x^{3}}
  2. 2

    Direct substitution gives an indeterminate form: 0/0. It does not tell us the limit.

  3. 3

    L'HΓ΄pital's rule: when the form is 0/0, the limit equals the limit of the ratio of the derivatives.

    lim⁑sin⁑(x)βˆ’xx3=lim⁑cos⁑(x)βˆ’13x2\lim \frac{\sin\left(x\right) - x}{x^{3}} = \lim \frac{\cos\left(x\right) - 1}{3 x^{2}}
  4. 4

    Still 0/0 (both vanish again), so apply it once more.

    lim⁑cos⁑(x)βˆ’13x2=limβ‘βˆ’sin⁑(x)6x\lim \frac{\cos\left(x\right) - 1}{3 x^{2}} = \lim \frac{-\sin\left(x\right)}{6 x}
  5. 5

    Still 0/0 (both vanish again), so apply it once more.

    limβ‘βˆ’sin⁑(x)6x=limβ‘βˆ’cos⁑(x)6\lim \frac{-\sin\left(x\right)}{6 x} = \lim \frac{-\cos\left(x\right)}{6}
  6. 6

    Now substitute x = 0: the denominator is not 0 any more.

    βˆ’16=βˆ’0.16666667\frac{-1}{6} = -0.16666667
  7. 7

    Method: series: sin x = x βˆ’ xΒ³/6 + ….

  8. 8

    Result:

    lim⁑xβ†’0sin⁑(x)βˆ’xx3=βˆ’16\lim_{x \to 0} \frac{\sin\left(x\right) - x}{x^{3}} = -\frac16
LaTeX source of the formulas on this page
\[ \lim_{x \to 0} \frac{\sin\left(x\right) - x}{x^{3}} = -\frac16 \]
\[ \lim_{x \to 0} \frac{\sin\left(x\right) - x}{x^{3}} \]
\[ \lim \frac{\sin\left(x\right) - x}{x^{3}} = \lim \frac{\cos\left(x\right) - 1}{3 x^{2}} \]
\[ \lim \frac{\cos\left(x\right) - 1}{3 x^{2}} = \lim \frac{-\sin\left(x\right)}{6 x} \]
\[ \lim \frac{-\sin\left(x\right)}{6 x} = \lim \frac{-\cos\left(x\right)}{6} \]
\[ \frac{-1}{6} = -0.16666667 \]

Values of (sin(x) - x) / x3x^{3} as x β†’ 0 (computed)

xf(x)Distance from the limit
0.1-0.166583358.33e-5
-0.1-0.166583358.33e-5
0.01-0.166665838.33e-7
-0.01-0.166665838.33e-7
0.001-0.166666668.33e-9
-0.001-0.166666668.33e-9
0.0001-0.166666665.18e-9
-0.0001-0.166666665.18e-9
0.00001-0.166667286.18e-7
-0.00001-0.166667286.18e-7

Questions

What is the limit of (sin(x) - x) / x3x^{3} as x approaches 0?

The limit of sin⁑(x)βˆ’xx3\frac{\sin\left(x\right) - x}{x^{3}} as xβ†’0x \to 0 is βˆ’16-\frac16.

Which form is it?

0/0.

More well-known limits

    Limit of (sin(x) - x) / x^3 as x β†’ 0: βˆ’1/6 | WordGPT