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Limit of sin⁡(3x)x\frac{\sin\left(3 x\right)}{x} as x→0x \to 0

The limit of sin⁡(3x)x\frac{\sin\left(3 x\right)}{x} as x→0x \to 0 is 33.

Graph of sin(3x) / x near x = 0-1.5-1-0.50.511.5-1123limit = 3f(x)
Graph of sin(3x) / x near x = 0. The open circle marks the point x = 0, where the function may be undefined; the curve still heads to 3.

How to work it out

  1. 1

    We want what sin(3x) / x approaches as x → 0.

    lim⁡x→0sin⁡(3x)x\lim_{x \to 0} \frac{\sin\left(3 x\right)}{x}
  2. 2

    Direct substitution gives an indeterminate form: 0/0. It does not tell us the limit.

  3. 3

    L'Hôpital's rule: when the form is 0/0, the limit equals the limit of the ratio of the derivatives.

    lim⁡sin⁡(3x)x=lim⁡3cos⁡(3x)1\lim \frac{\sin\left(3 x\right)}{x} = \lim \frac{3 \cos\left(3 x\right)}{1}
  4. 4

    Now substitute x = 0: the denominator is not 0 any more.

    31=3\frac{3}{1} = 3
  5. 5

    Method: write sin(3x)/x = 3 · sin(3x)/(3x) and use sin u / u → 1.

  6. 6

    Result:

    lim⁡x→0sin⁡(3x)x=3\lim_{x \to 0} \frac{\sin\left(3 x\right)}{x} = 3
LaTeX source of the formulas on this page
\[ \lim_{x \to 0} \frac{\sin\left(3 x\right)}{x} = 3 \]
\[ \lim_{x \to 0} \frac{\sin\left(3 x\right)}{x} \]
\[ \lim \frac{\sin\left(3 x\right)}{x} = \lim \frac{3 \cos\left(3 x\right)}{1} \]
\[ \frac{3}{1} = 3 \]

Values of sin(3x) / x as x → 0 (computed)

xf(x)Distance from the limit
0.12.95520214.48e-2
-0.12.95520214.48e-2
0.012.99955004.50e-4
-0.012.99955004.50e-4
0.0012.99999554.50e-6
-0.0012.99999554.50e-6
0.00013.00000004.50e-8
-0.00013.00000004.50e-8
0.000013.00000004.50e-10
-0.000013.00000004.50e-10

Questions

What is the limit of sin(3x) / x as x approaches 0?

The limit of sin⁡(3x)x\frac{\sin\left(3 x\right)}{x} as x→0x \to 0 is 33.

Which form is it?

0/0.

More well-known limits

    Limit of sin(3x) / x as x → 0: 3 | WordGPT