Integral of
The integral of is .
How to work it out
- 1
We want an antiderivative of f(x) = * exp(x).
- 2
Method: integration by parts twice.
- 3
That gives the antiderivative; add the constant C because any constant disappears when you differentiate:
- 4
Check by differentiating the answer; you must get the original function back:
- 5
As a definite integral, evaluate the antiderivative at both ends and subtract. Between 0 and 1:
LaTeX source of the formulas on this page
\[ \int x^{2} e^{x}\,dx = \left(x^{2} - 2 x + 2\right) e^{x} + C \]
\[ \int x^{2} e^{x}\,dx \]
\[ \frac{d}{dx}\left[\left(x^{2} - 2 x + 2\right) e^{x}\right] = \left(2 x - 2\right) e^{x} + \left(x^{2} - 2 x + 2\right) e^{x} \]
\[ \int_{0}^{1} x^{2} e^{x}\,dx = \Big[\left(x^{2} - 2 x + 2\right) e^{x}\Big]_{0}^{1} \approx 0.71828183 \]Definite integrals of the same function
| Interval | Value |
|---|---|
| from 0 to 1 | 0.71828183 |
| from 0 to 0.5 | 0.060901588 |
Questions
What is the integral of * exp(x)?
The integral of is .
Why do we add + C?
Every function F(x) + C has the same derivative, so the antiderivative is only defined up to a constant.
What is the integral of * exp(x) from 0 to 1?
About 0.71828183.