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Which is bigger, 292^{9} or 929^{2}?

292^{9} is bigger: 292^{9} = 512 and 929^{2} = 81.

The curve ln x / x, which decides every comparison of a^b with b^a24681012-0.8-0.6-0.4-0.20.20.4x = 2x = 9peak at eln x / x
The curve ln x / x, which decides every comparison of a^b with b^a. 2^9 against 9^2 is the same question as which of the two marked points is higher; the curve peaks at x = e.

How to work it out

  1. 1

    Compute both exactly: 292^{9} = 512 and 929^{2} = 81.

  2. 2

    So 292^{9} is bigger.

  3. 3

    The reason: taking logs, aba^{b} against bab^{a} is the same as ln⁡aa\frac{\ln a}{a} against ln⁡bb\frac{\ln b}{b}. The function ln⁡xx\frac{\ln x}{x} rises until x=e≈2.718x = e \approx 2.718 and falls afterwards. For 2 and 9 it depends: 242^{4} = 424^{2} are equal, 232^{3} < 323^{2}, and 2b2^{b} > b2b^{2} for every b ≥ 5.

    ln⁡22 > ln⁡99\frac{\ln 2}{2}\ >\ \frac{\ln 9}{9}
LaTeX source of the formulas on this page
\[ 2^{9} = 512\ >\ 9^{2} = 81 \]
\[ \frac{\ln 2}{2}\ >\ \frac{\ln 9}{9} \]

Questions

Which is bigger, 292^{9} or 929^{2}?

292^{9} is bigger: 292^{9} = 512 and 929^{2} = 81.

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