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Which is bigger, 282^{8} or 828^{2}?

282^{8} is bigger: 282^{8} = 256 and 828^{2} = 64.

The curve ln x / x, which decides every comparison of a^b with b^a246810-0.8-0.6-0.4-0.20.20.4x = 2x = 8peak at eln x / x
The curve ln x / x, which decides every comparison of a^b with b^a. 2^8 against 8^2 is the same question as which of the two marked points is higher; the curve peaks at x = e.

How to work it out

  1. 1

    Compute both exactly: 282^{8} = 256 and 828^{2} = 64.

  2. 2

    So 282^{8} is bigger.

  3. 3

    The reason: taking logs, aba^{b} against bab^{a} is the same as ln⁡aa\frac{\ln a}{a} against ln⁡bb\frac{\ln b}{b}. The function ln⁡xx\frac{\ln x}{x} rises until x=e≈2.718x = e \approx 2.718 and falls afterwards. For 2 and 8 it depends: 242^{4} = 424^{2} are equal, 232^{3} < 323^{2}, and 2b2^{b} > b2b^{2} for every b ≥ 5.

    ln⁡22 > ln⁡88\frac{\ln 2}{2}\ >\ \frac{\ln 8}{8}
LaTeX source of the formulas on this page
\[ 2^{8} = 256\ >\ 8^{2} = 64 \]
\[ \frac{\ln 2}{2}\ >\ \frac{\ln 8}{8} \]

Questions

Which is bigger, 282^{8} or 828^{2}?

282^{8} is bigger: 282^{8} = 256 and 828^{2} = 64.

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