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Which is bigger, 182818^{28} or 281828^{18}?

182818^{28} is bigger: 182818^{28} = 1.40485 × 103510^{35} and 281828^{18} = 1.11903 × 102610^{26}.

The curve ln x / x, which decides every comparison of a^b with b^a510152025300.10.150.20.250.30.350.4x = 18x = 28peak at eln x / x
The curve ln x / x, which decides every comparison of a^b with b^a. 18^28 against 28^18 is the same question as which of the two marked points is higher; the curve peaks at x = e.

How to work it out

  1. 1

    Compute both exactly: 182818^{28} = 140485060518220186283313934500888576 and 281828^{18} = 111903730358193158266814464.

  2. 2

    So 182818^{28} is bigger.

  3. 3

    The reason: taking logs, aba^{b} against bab^{a} is the same as ln⁡aa\frac{\ln a}{a} against ln⁡bb\frac{\ln b}{b}. The function ln⁡xx\frac{\ln x}{x} rises until x=e≈2.718x = e \approx 2.718 and falls afterwards. Both 18 and 28 are past e, where the function is decreasing, so the larger exponent loses and 182818^{28} > 281828^{18}.

    ln⁡1818 > ln⁡2828\frac{\ln 18}{18}\ >\ \frac{\ln 28}{28}
LaTeX source of the formulas on this page
\[ 18^{28} = 1.40485\times 10^{35}\ >\ 28^{18} = 1.11903\times 10^{26} \]
\[ \frac{\ln 18}{18}\ >\ \frac{\ln 28}{28} \]

Questions

Which is bigger, 182818^{28} or 281828^{18}?

182818^{28} is bigger: 182818^{28} = 1.40485 × 103510^{35} and 281828^{18} = 1.11903 × 102610^{26}.

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